A beam of light propagating in medium A with index of refraction n (A) passes across an interface into medium B with index of refraction n(B). The angle of incidence is greater than the angle of refraction; v(A) and v(B) denotes the speed of light in A and B. Then which of the following is true

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v(A)>v(B) and n(A)>n(B)

ν(A)>v(B) and n(A)

v(A)n(B)

v(A)

answer is B.

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Detailed Solution

∵∠i>∠r, it means light ray is going from rarer medium (A) to denser medium. So v(A)>v(B) and n(A)

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