First slide
Introduction-Electromagnetic waves
Question

A beam of light travelling along x-axis is described by the electric field EY=(600Vm1)sinω(txc),  then the maximum magnetic force on a charge q=2e moving along y-axis with a speed of 3×107m/s is (where e=1.6×1019 C)

Moderate
Solution

Amplitude of magnetic field is  B0=E0C=6003×108=2×106T
( from the given equation,  E0=600V/m)
Maximum magnetic force is  F=qvB0=2evB0
 F=2×1.6×1019×3×107×2×106
 F=1.92×1017N

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