A beam of light travelling along $$x-axis$$ is described by the electric field $$EY=(300Vm$$−$$1)$$$$sin$$ω(t$$−$$xC). Calculate the maximum magnetic force on a charge $$q=4e$$, moving along $$y-axis$$ with a speed of $$2$$×$$107m/s$$ is (where$$ $$e=1.6$$×$$10$$−$$19C$$ $$)

Question

A beam of light travelling along $$x-axis$$ is described by the electric field  $$EY=(300Vm$$−$$1)$$$$sin$$ω(t$$−$$xC). Calculate the maximum magnetic force on a charge  $$q=4e$$, moving along $$y-axis$$ with a speed of $$2$$×$$107m/s$$ is (where$$ $$e=1.6$$×$$10$$−$$19C$$ $$)

Infinity Learn · Accepted Answer

Amplitude of magnetic field is  $$B0=E0C=3003$$×$$108=1$$×$$10$$−$$6T($$ From the given equation  $$E0=300V/m)Maximum$$ magnetic force $$isFm=qVB0=4eVB0$$ ⇒$$Fm=4$$×$$1.6$$×$$10$$−$$19$$×$$2$$×$$107$$×$$1$$×$$10$$−$$6$$⇒$$Fm=12.8$$×$$10$$−$$18$$     ⇒  $$Fm=1.28$$×$$10$$−$$17N$$

A beam of light travelling along x-axis is described by the electric field $E_{Y} = (300 V m^{- 1}) \sin ω (t - \frac{x}{C})$ . Calculate the maximum magnetic force on a charge $q = 4 e$ , moving along y-axis with a speed of $2 \times 10^{7} m / s$ is (where $e = 1.6 \times 10^{- 19} C$ )

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A beam of light travelling along x-axis is described by the electric field EY=(300Vm−1)sinω(t−xC). Calculate the maximum magnetic force on a charge q=4e, moving along y-axis with a speed of 2×107m/s is (where e=1.6×10−19C )

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A beam of light travelling along x-axis is described by the electric field $E_{Y} = (300 V m^{- 1}) \sin ω (t - \frac{x}{C})$ . Calculate the maximum magnetic force on a charge $q = 4 e$ , moving along y-axis with a speed of $2 \times 10^{7} m / s$ is (where $e = 1.6 \times 10^{- 19} C$ )