A beam of light travelling along x-axis described by the magnetic field, Bz=5×10−10sinw(t−Xc)T . Calculate the maximum magnetic force on alpha particle, moving along y-axis with a  speed of  3×107m/s. Charge on electron is  1.6×10−19C.

Force on the alpha particle due to magnetic field is F=qvB sin(90o) Given : Bz=5×10−10sinw(t−xc)T Comparing with Bz=Bosinw(t−xc)T ∴Bo=5×10−10T Hence,  F = qvB      [Charge on alpha particle = +2e] ⇒F=2×1.6×10−19×3×107×5×10−10 ⇒F=48×10−22N