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Q.

A beam of protons with speed  4×105ms−1 enters a uniform magnetic field of 0.3T at an angle of 60º to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton  1.67×10−27kg,  charge of the proton 1.69×10−19 C)

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a

12cm

b

4cm

c

2cm

d

5cm

answer is B.

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Detailed Solution

pitch=Vcosθ.T=Vcosθ×2πmqB​⇒pitch=4×105×cos60º×2π×1.67×10−271.69×10−19×0.3​⇒pitch=1.67×4π1.69×0.3×10−3m≃4cm
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