First slide

Heat engine

Question

The below P-V digram represents the thermodynamic cycle of an engine, operating with and ideal monoatomic gas. The amount of heat extracted from the source in a single cycle is

Easy

A

$\left( {\frac{{13}}{2}} \right){p_0}{v_0}$
B

$\left( {\frac{{11}}{2}} \right){p_0}{v_0}$
C

$4{p_0}{v_0}$
D

${p_0}{v_0}$

Solution

${Q_{DA}} = ncv\Delta T = \frac{{nR\Delta T}}{{\gamma - 1}} = \frac{{3{P_0}{V_0}}}{2}$
${Q_{AB}} = n{C_p}\Delta T = n\frac{{\gamma R}}{{\left( {\gamma - 1} \right)}}\Delta T$
$\Rightarrow {Q_{AB}} = \frac{5}{2}\left( {4{P_0}{V_0} - 2{P_0}{V_0}} \right)$
= 5P₀V₀
${Q_{DA}} + {Q_{AB}} = \frac{{3{P_0}{V_0}}}{2} + 5{P_0}{V_0} = \frac{{13{P_0}{V_0}}}{2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App