Questions

In a bent wire shown in figure, a current I is passed. Find the value of B at the common centre.

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μ0Ib−a 2π−θ4πab

μ0la 2π−θ4πb

μ0la 2π−θ4πa

μ0lab θ4π

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detailed solution

Correct option is A

The straight segments make no contribution to the field at the centre. By Biot-Savart's law, the field at the centre due to curved segments isΔB=μ0I4πa 2π−θa2 − b 2π−θb2=μ0I4π 2π−θ 1a −1b = μ0I2π−θ b−a 4πab

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