Between the plates of a parallel plate condenser a plate of thickness t1 and dielectric constant k1 is placed. In the rest of space there is another plate of thickness t2 and dielectric constant k2. The potential difference across the condenser will be
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a
QAε0t1k1+t2k2
b
ε0QAt1k1+t2k2
c
QAε0k1t1+k2t2
d
ε0QA(k1t1+k2t2)
answer is A.
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Detailed Solution
Potential difference across the condenserV=V1+V2=E1t1+E2t2=σK1ε0t1+σK2ε0t2 ⇒V=σε0t1K1+t2K2=QAε0t1K1+t2K2