A bi-convex lens made of glass (refractive index 1.5) is put in a liquid of refractive index 1.7. Its focal length will
Decrease and change sign
Increase and change sign
Decrease and remain of the same sign
Increase and remain of the same sign
flfa=aμg−1ug−1=(1.5−1)×1.7(1.5−1.7) ⇒fl=0.85−0.2fa=−4.25fa