First slide

Work done by Diff type of forces

Question

A bicyclist comes to a skidding stop in 10m. During this process, the force on the bicycle due to the road is 200 N and is directly opposed to the motion. The work
done by the cycle on the road is [NCERT Exemplar]

Moderate

A

+ 2000 J
B

$-$ 200 J
C

zero
D

$-$ 20000 J

Solution

Here, work is done by the frictional force on the cycle and is equal to
$-$ 200 x 10 = $-$ 2000 J. As the road is not moving, hence work done by the cycle on the road = zero.

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