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A bimetallic strip is formed out of two identical strips, one of copper and the other of brass. The coefficients of linear expansion of the two metals are αC and αB. On heating, the temperature of the strip goes up by T and the strip bends to form an arc of radius of curvature R. Then R is :
(i) proportional to T
(ii) inversely proportional to T
(iii) proportional to αB-αC
(iv) inversely proportional to αB-αC

a
(i, ii)
b
(i, iii)
c
(ii, iv)
d
(i, iv)

detailed solution

Correct option is C

Length of brass rod LB=Lo(1+αB∆T)=(R+d)θ  Length of copper rod LC=Lo(1+αc∆T)      =(R-d)θ ⇒R+dR-d=1+αB∆T1+αC∆T ⇒2R2d=2+(αB+αC)∆T(αB-αC)∆T Since   (αB+αC)∆T <<<2 ∴  R=2d(αB-αC)∆T.

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Two thin metal strips each of 2mm thick, one of brass and the other of iron are fastened   together  parallel to each other, to form  a bimetallic strip. If the strips are  of equal  length  at 0°c . The radius of the arc  formed  by the  bimetallic strip when heated to C is (Coefficient of linear expansion of brass =  19×106/C  and of iron = 12×106/C )


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