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Q.

The binding energies per nucleon are 5.3 MeV, 6.2 MeV and 7.4 MeV for the nuclei with mass numbers 3,4 and 5 respectively. If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei of mass number 4, then

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a

0.3 MeV of energy absorbed

b

0.3 MeV of energy is released

c

2.81 MeV energy is absorbed

d

3.3 MeV energy is absorbed

answer is D.

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Detailed Solution

A3+B5→2C4 B.AA=3×5.3=15.9MeVB.AB=5×7.4=37MeVB.AC=2×4×6.2=49.6MeVEp−ER=+Ve  Energy releasedEp−ER=−Ve  Energy absorbed∴Ep−ER=49.6−(15.9+3.7)                    =−3.3∴3.3MeV  of energy is absorbed
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