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The binding energies per nucleon are 5.3 MeV, 6.2 MeV and 7.4 MeV for the nuclei with mass numbers 3, 4 and 5 respectively. If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei with mass number 4. Then

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answer is 4.

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Detailed Solution

Bi=3 × 5.3+5 × 7.4 MeV=52.9 MeV Bf= 4 × 6.2 × 2 MeV = 49.6 MeVSince Bi > Bf, energy is absorbed∴Energy absorbed = Bi − Bf=3.3 MeV

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The binding energies per nucleon are 5.3 MeV, 6.2 MeV and 7.4 MeV for the nuclei with mass numbers 3, 4 and 5 respectively. If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei with mass number 4. Then