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Q.

The binding energies per nucleon are 5.3 MeV, 6.2 MeV and 7.4 MeV for the nuclei with mass numbers 3, 4 and 5 respectively. If one nucleus of mass number 3 combines with one nucleus of mass number 5 to give two nuclei with mass number 4. Then

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answer is 4.

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Detailed Solution

Bi=3  ×  5.3+5  ×  7.4 MeV=52.9  MeV  Bf=  4  ×  6.2 ×  2    MeV  =  49.6  MeVSince Bi > Bf, energy is absorbed∴Energy absorbed = Bi  −   Bf=3.3  MeV
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