First slide

Nuclear Binding energy

Question

The binding energy per nucleon for C¹² is 7.68 MeV and that for C¹³ is 7.47 MeV. The energy required to remove a neutron from C¹³ is

Moderate

A

0.21 MeV
B

2.52 MeV
C

4.95 MeV
D

2.75 MeV

Solution

$\begin{array}{rcl} C^{13} & \to & C^{12} + {}_{0}n^{1} \\ For C^{13} & \to & {BE}_{1} = 13 (7.47) = 97.11 \\ For C^{12} & \to & {BE}_{2} = 12 (7.68) = 92.16 \end{array}$
Energy required = 97.11 – 92.16 = 4.95 Mev

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