Q.

The binding energy per nucleon of deuterium and helium atom  is 1.1 MeV and 7.0 MeV. If two deuterium nuclei fuse to form helium atom, the energy released is

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a

19.2 MeV

b

23.6 MeV

c

26.9 MeV

d

13.9 MeV

answer is B.

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Detailed Solution

H 2 1 +H 2 1 →He 4 2 +energyBinding energy of a (H 2 1 ) deuterium nuclei = 2 x 1.1 = 2.2MeV Total binding energy of two deuterium nuclei = 2.2 x 2 = 4.4MeVBinding energy of a (He 4 2 ) nuclei = 4 x 7 = 28MeV So, energy released in fusion = 28 - 4.4 = 23.6 MeV
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The binding energy per nucleon of deuterium and helium atom  is 1.1 MeV and 7.0 MeV. If two deuterium nuclei fuse to form helium atom, the energy released is