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Q.

The binding energy per nucleon for Deuteron and Helium 1H2 and 2He4 are 1.1 MeV and 7 MeV respectively. The energy released when two Deuterons fuse to form a Helium nucleus is

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a

1.1 MeV

b

7 MeV

c

23.6 MeV

d

6 MeV

answer is C.

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Detailed Solution

H 2 1 +H 2 1 →H 4 2  For each H 2 1 →BE1=2(1.1)=2.2 MeV For He 4 2 →BE2=4(7)=28 MeV E=BE2–2BE1 = 28–2(2.2) = 23.6 MeV
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