Q.

The binding energy per nucleon of  L 37iand H 24e Nuclei are 5.60 MeV  and 7.06 MeV respectively. In the nuclear reactionLi 37+H 11→He 24+He 24+Qthe value of energy Q released is

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a

19.6 MeV

b

-2.4 MeV

c

8.4 MeV

d

17.3 MeV

answer is B.

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Detailed Solution

Binding energy of Li 37 nucleus =7×5.60MeV=39.2MeV Binding energy of  Henucleus  24=4×7.06MeV=28.24MeVthe reaction isLi 37+H 11→2He 24+Q∴Q=2BE of He 24-BE of Li 37=2×28.24MeV-39.2MeV=56.48MeV-39.2MeV=17.28MeV≈17.3MeV
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The binding energy per nucleon of  L 37iand H 24e Nuclei are 5.60 MeV  and 7.06 MeV respectively. In the nuclear reactionLi 37+H 11→He 24+He 24+Qthe value of energy Q released is