The Binding energy per nucleon of Li 37 and He 24 nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction Li 37+H 11→He 24+He 24+Q the value of energy Q released is
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a
-2.4 MeV
b
8.4 MeV
c
17.3 MeV
d
19.6 MeV
answer is C.
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Detailed Solution
B.E of Li 7 3 =7 x 5.60 Mev=39.2 MevB.E of He 4 2 =4 x 7.06 Mev=28.24 MevQ=2B.E of He 4 2 -B.E of Li 7 3 =(2 x 28.24) – 39.2=17.28 Mev
The Binding energy per nucleon of Li 37 and He 24 nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction Li 37+H 11→He 24+He 24+Q the value of energy Q released is