First slide

Nuclear Binding energy

Question

The binding energy per nucleon of $O^{16} is 7.97 MeV$ and that of $O^{17} is 7.75 MeV$ . The energy (in MeV) required to remove a neutron from $O^{17}$ is

Moderate

A

3.52
B

3.64
C

4.23
D

7.86

Solution

The equation is $O^{17} \to {}_{0}n^{1} + O^{16}$
$∴$ Energy required $= B . E . of O^{17} - B . E . of O^{16}$
= 17 x 7.75-16 x 7.97 = 4.23 MeV.

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