First slide

Nuclear Binding energy

Question

The binding energy per nucleon of $O^{16}$ is 7.97 MeV and that of $O^{17}$ is 7.75 MeV. The energy (in MeV)
required to remove a neutron from $O^{17}$ is

Easy

A

3.52
B

3.64
C

4.23
D

7.86

Solution

The equation is $O^{17} \to_{0} n^{1} + O^{16}$
$∴$ Energy required = B.E. of $O^{17} - B . E . of O^{16}$
= 17 x 7.75 – 16 x 7.97 = 4.23 MeV

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App