A bird is diving vertically downwards a fish in water with a velocity of 5 m/s. At the same time the fish is moving vertically downward away from the bird. If the distance of the fish as viewed by the bird remains unchanged, then velocity of the fish is μ=4/3

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7.67 m/s

5.62 m/s

4.32 m/s

6.67 m/s

answer is D.

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Detailed Solution

Distance of the fish as observed by the bird is given by =ZF/B=x+yμ∴ ddtZF/B=dxdt+1μdydt=−VB+1μVFSince ZF/B is constant, we can write −VB+1μVF=O⇒VF=μVB=43×5 m/s=6.67 m/s

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