Q.
A bird is flying towards north with a velocity 40km/h and a train is moving with a velocity 40km/h towards east. What is the velocity of the bird noted by a man in the train?
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a
402km/h N−E
b
402km/h S−E
c
402km/h N−W
d
402km/h S−W
answer is C.
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Detailed Solution
To find the relative velocity of bird w.r.t train, superimpose velocity−V→T on both the objects. Now as a result of it, the train is at rest,while bird posses two velocities −V→B towards N and −V→T along west.Where, −V→B = Velocity of bird −V→T = Velocity of train.|V→BT|=|V→B|2+|−V→T|2[By formula, ∴ θ=900 ]=402+402=402km/hr North−West
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