Q.

A black body is heated from 70C to 2870C. The ratio of radiation emitted is

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a

1 : 256

b

1 : 27

c

1 : 16

d

1 : 64

answer is C.

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Detailed Solution

Given: Initial temperature, T1 = 70C = 280 KFinal temperature, T2= 2870C = 560 KAccording to Stefan's law the radiated energy is given yE ∝ T4Hence E1E2 = T14T24 = (280560)4= 116    E1 : E2 = 1 : 16
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A black body is heated from 70C to 2870C. The ratio of radiation emitted is