Questions
A black body is heated from27° to 127°C. The ratio of their energies of radiation emitted will be
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a
81 : 256
b
27 : 64
c
9 : 16
d
3 : 4
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Correct option is A
From Stefan's law, the total radiant energy emitted per second per unit surface area of a black body is proportional to the fourth power of the absolute temperature of the body.That is E = σT4where σ is Stefan's constant.Given,initial temperature T1 = 273 + 27 = 300Kfinal temperature T2 = 127 + 273 = 400 KHence, we haveE1E2 = T41T42 = (300)4(400)4 = 81256Therefore, E1 : E2 = 81 : 256Similar Questions
For a black body at temperature 727°C, its radiating power is 60W and temperature of surrounding is 227° C. If temperature of black body is changed to 1227°C, then its
radiating power will be :
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