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A black body radiates power P and maximum energy is radiated by it around a wavelength $λ_{0}$ . The temperature of the black body is now changed such that it radiates maximum energy around the wavelength $\frac{3 λ_{0}}{4}$ The power radiated by it now is :

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detailed solution

Correct option is A

λmT=constantλ→3λ04T→4T03P∝T425681P=P'

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A black body radiates power P and maximum energy is radiated by it around a wavelength λ0 . The temperature of the black body is now changed such that it radiates maximum energy around the wavelength 3λ04 The power radiated by it now is :

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Ready to Test Your Skills?

free study material

A black body radiates power P and maximum energy is radiated by it around a wavelength $λ_{0}$ . The temperature of the black body is now changed such that it radiates maximum energy around the wavelength $\frac{3 λ_{0}}{4}$ The power radiated by it now is :