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A black body radiates 20 W at temperature $227^{0} C . If temperature of the black body is changed o 727^{0} C, then$ its radiating power will be:

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120 W

240 W

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360 W

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detailed solution

Correct option is C

For a black body Qt = P = AσT4⇒ P2P1 = (T2T1)4 ⇒ P220= (273+727273+227)4⇒ P220 = (2)4 ⇒ P2 = 320 W

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A black body radiates 20 W at temperature 2270C. If temperature of the black body is changed o 7270C, then its radiating power will be:

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A black body radiates 20 W at temperature $227^{0} C . If temperature of the black body is changed o 727^{0} C, then$ its radiating power will be: