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Q.

A black body radiates 20 W at temperature 2270C. If temperature of the black body is changed o 7270C, then its radiating power will be:

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a

120 W

b

240 W

c

320 W

d

360 W

answer is C.

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Detailed Solution

For a black body Qt = P = AσT4⇒  P2P1 = (T2T1)4     ⇒  P220= (273+727273+227)4⇒ P220 = (2)4    ⇒  P2 = 320 W
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