Questions
A black body of surface area 10 cm2 is heated to 127°C and is suspended in a room at temperature 27°C. The rate of loss of heat is
detailed solution
Correct option is A
Applying Stefan's law, we have dEdt=σAT14−T04=5⋅67×10−8×10×10−4(400)4−(300)4=1 watt.Talk to our academic expert!
Similar Questions
For a black body at temperature 727°C, its radiating power is 60W and temperature of surrounding is 227° C. If temperature of black body is changed to 1227°C, then its
radiating power will be :
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