Q.

A black body is at a temperature of 2800 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U1 and between 999 nm and 1000 nm is U2. The Wien constant, b = 2.80 x 106 nmK. Then

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a

U1=0

b

U2=0

c

U1>U2

d

U2>U1

answer is D.

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Detailed Solution

λmT=b or    λm=bT=2⋅80×1062800=1000 nm Hence,  U2 is maximum. Thus, U2>U1
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A black body is at a temperature of 2800 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is U1 and between 999 nm and 1000 nm is U2. The Wien constant, b = 2.80 x 106 nmK. Then