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Q.

A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant b = 2.88 x 106 nm K. Then

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a

U1=0

b

U3=0

c

U1>U2

d

U2>U1

answer is D.

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Detailed Solution

According to Wien's displacement law, λmT=b  or  λm=b/T∴ λm=2.88×106nm2880K=1000nm. This shows that U2 is maximum.Further, black body spectrum is continuous. Hence, finite radiant energy is emitted at all wavelengths, i e ,U1≠0 and U3≠0Thus,  U2>U1.
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