In a black box of unknown elements (L or R or any other combination), an ac voltageE=E0 sin ωt+ϕ is applied and current in the circuit was found to be I=I0 sin ωt+ϕ+π/4. Then the unknown elements in the box may be
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a
only capacitor
b
inductor and resistor both
c
either capacitor, resistor, and inductor or only capacitor and resistor
d
only resistor
answer is C.
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Detailed Solution
Since current is leading emf, capacitor must be present in the circuit. Along with capacitor, there can be either (i) only resistoror (ii) resistor and inductor if XC > XLIn both of the above conditions, we can obtain a phase difference ofπ/4 with current leading emf