A Black metal foil receives radiation of power P from a hot sphere at absolute temperature T, kept at a distance d. If the temperature is doubled and distance is halved, then Power will be

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64P

16P

answer is A.

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Detailed Solution

P=eAσT4d2PαT4d2P1P2=T14T24×d22d12P1P2=116×14P2=64P

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