A block attached between two springs is in equilibrium. If the upper spring is cut, then the acceleration of the block just after cut is ${6 m/s}^{2}$ downwards. Now, if instead of upper spring, the lower spring is cut, then the magnitude of acceleration of the block, just after the cut will be (Take g = ${10 m/s}^{2}$ and identical springs)

Question

Infinity Learn · Accepted Answer

For  equillibrium, $$FU+FL=mg$$           ...iWhen $$FU=0$$, mg−$$FL=m$$×$$6$$⇒$$FL=10m$$−$$6m=4mAgain$$,when $$FL=0$$,   mg−$$FU=ma$$⇒$$a=mg$$−$$FUm=mg$$−mg−FLm        ∵$$FU=mg$$−FL $$=FLm=4mm$$⇒a $$=$$ $$4$$ $$m/s2$$

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material