A block attached between two springs is in equilibrium. If the upper spring is cut, then the acceleration of the block just after cut is 6 m/s2 downwards. Now, if instead of upper spring, the lower spring is cut, then the magnitude of acceleration of the block, just after the cut will be (Take g = 10 m/s2 and identical springs)

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16 m/s2

4 m/s2

10 m/s2

None of these

answer is B.

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Detailed Solution

For equillibrium, FU+FL=mg ...iWhen FU=0, mg−FL=m×6⇒FL=10m−6m=4mAgain,when FL=0, mg−FU=ma⇒a=mg−FUm=mg−mg−FLm ∵FU=mg−FL =FLm=4mm⇒a = 4 m/s2

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