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Q.

A block is attached to a horizontal spring of stiffness k. The other end of the spring is attached to a fixed wall. The entire system lie on a horizontal surface and the spring is in natural state. The natural length of the spring is ℓ0If the block is slowly lifted up vertically to a height 512ℓ0 from its initial position, which of the following is not correct:

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a

The work done by the gravity 512ℓ0mg

b

The work done by the spring force −kℓ02288

c

The work done by the 512mgℓ0+kℓ02288 lifting force

d

The sum of works done by all the forces on the block is zero

answer is A.

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Detailed Solution

Change in kinetic energy of the block is zero. Hence by work energy theorem ,option 4 is write.Again elongation produced in the spring =l012.So work done by the spring = -Elastic PE stored in the spring=-kl02288Work done by the gravity force= -5mgl012By work energy theorem , WF+Wg+WS=0 ⇒WF=5mgl012+kl02288 Hence option1 is wrong

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