First slide

Inertial and uniformly accelerated frame of reference

Question

Block B has mass m and is released from rest when it is on top of wedge A, which has a mass 3m. Determine the tension in cord CD needed to hold the wedge from moving while B is sliding down A. Neglect friction.

Moderate

A

$2 m g \cos θ$
B

$\frac{m g}{2} \cos θ$
C

$\frac{m g}{2} \sin 2 θ$
D

$m g \sin 2 θ$

Solution

$\begin{array}{l} T = N \cdot \sin θ and N = m g \cos θ \\ T = m g \cos θ \sin θ = \frac{m g}{2} \sin 2 θ \end{array}$

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