Block B lying on a table weighs w. The coefficient of static friction between the block and the table is μ. Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

Question

Block B lying on a table weighs w. The coefficient of static friction between the block and the table is μ. Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

Infinity Learn · Accepted Answer

Let weight of A is w'. From the free body diagram, for equilibrium of the system,T $$cos$$θ $$=$$ μN $$=$$ μw        ..........(i)T$$ $$sin$$θ $$=$$ w'        ..........$$(ii)where$$, T $$=$$ tension in the thread lying between knot and the support.On dividing Eq. $$(ii) by Eq. (i), we getTsinθTcosθ$$=w$$'μw⇒$$tan$$θ$$=w$$'μw⇒  w'$$=$$μwtanθ

Block B lying on a table weighs w. The coefficient of static friction between the block and the table is $μ$ . Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

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