A block B of mass 2 kg is placed on the rough inclined surface of a wedge W. The wedge is kept on a smooth horizontal floor and held in position by an external agent. The block is in equilibrium on the wedge. If the wedge slowly moves to the left by 5m,
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Work done by force of friction on the block is -203J
b
Work done by normal force acting on the block is +253J
c
Work done by force of friction on the block is +253J
d
None of the above is correct.
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
f=mgsinθ and N=mgcosθ∴ f=2×10×sin30oN=10 NN=2×10×cos30oN=103 N∴ Wf=−fcosθS=−10×cos30o×5J=−253 JWN=Nsinθ×S=103×sin30o×5 J=+253 J