A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be
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a
0.4ms−2
b
0.5ms−2
c
1ms−2
d
zero
answer is C.
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Detailed Solution
Maximum force up to which A and B will move together is given by Fmax=μsmg(1+m/M) where m = mass of B and M = mass of A.∴Fmax=0.4×5×10(1+5/20)N⇒25N A and B will move together and their acceleration is a=2520+5m/s2=1m/s2