A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be
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a
0.4ms–2
b
0.5ms–2
c
1ms–2
d
zero
answer is C.
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Detailed Solution
Maximum force upto which A and B will move together is given by. Fmax = µsmg(1+m/M), where m = mass of B and M = mass of A. Fmax = 0.4 x 5 x 10 (1+ 5/20)N ⇒ 25N so A and B will move together and their acceleration is
A block B of mass 5kg is placed on a slab A of mass 20kg which lies on a frictionless surface as shown in the figure. The coefficient of static friction between the block and the slab is 0.4 and that of kinetic friction is 0.2. If a force F = 25N acts on B, the acceleration of the slab will be