First slide

Stress and strain

Question

A block B of mass 20 Kg is suspended by a metallic rod of length 2 m, mass 10 Kg cross sectional area 4 mm² and young's modulus $2 \times 10^{10} N / m^{2}$ . Then elongation produced in the rod is

Moderate

A

8.25 mm
B

12.15 mm
C

4.85 mm
D

6.25 mm

Solution

$\begin{array}{l} δ = \frac{100 \times 1}{4 \times 10^{- 6} \times 2 \times 10^{10}} + \frac{200 \times 2}{4 \times 10^{- 6} \times 2 \times 10^{10}} m \\ \Rightarrow δ = (\frac{1}{800} + \frac{1}{200}) m = 6 .25 mm \end{array}$

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