Questions
A block C of mass m is moving with velocity v0 and collides elastically with block A of mass m and connected to another block B of mass 2m through spring of spring constant k. What is the value of k, if x0 is compression of spring, when velocity of A and B is same? [JIPMER 2017]
detailed solution
Correct option is D
Using the law of conservation of linear momentum, we have mv0=mv + 2mv ⇒ v=v0/3Using law of conservation of energy, we have 12mv02=12kx02+12(3m)v2where, x0 is compression in the spring.∴ mv02=kx02+(3m)v029⇒ kx02=mv02-mv023⇒kx02=2mv023∴ k=2mv023x02Talk to our academic expert!
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