Q.
A block is dragged on a smooth plane with the help of a rope which moves with a velocity v as shown in the figure. The horizontal velocity of the block is
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a
vsin θ
b
v sinθ
c
vcos θ
d
v cosθ
answer is A.
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Detailed Solution
Let at any instant of time, the length AB be l, here angle θ and length l vary with time, then using Pythagoras theorem in ∆ABC,x2 + y2 = t2On differentiating both sides w.r.t t, we getor 2xdxdt+2ydydt=2ldldtAs, there is no vertical motion of the block, sodydt=0,dxdt=vx and dldt=v∴ 2xvx = 2lv or vx=lxv or vx=vxl=vsinθ
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