A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:

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9.869×10−4N

6.28×10−3N

0.0314N

9.869×10−2N

answer is A.

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Detailed Solution

Angular velocity=ω=2πT=2π40 Normal reaction provides centripetal force. N=mrω2=2001000×20100×2π402=9.869×10−4N

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