Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A block of gelatin is 60 mm by 60 mm by 20 mm when unstressed. A force of 0.245N is applied tangentially to the upper surface , causing a 5 mm displacement relative to the lower surface. Following observations are made regarding the block.(i) the shearing stress developed on the surface is 68.1 Pa(ii) the shearing strain developed on surface is 0.25 Pa(iii) the shear modulus of material is 272.4  N/m2Regarding above statements we can say

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

Only statement (i) and (iii) are correct

b

Only statement (ii).and (iii) are correct

c

Only statements (i) and (ii) are correct

d

All the statements are correct.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Stress=FA=0.24536×10−4=68.1Pastrain=θ=rh=520=0.25Shear modulus=  S=FAtanθ=68.40.25=272.4N/m2
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon