Q.
A block of gelatin is 60 mm by 60 mm by 20 mm when unstressed. A force of 0.245N is applied tangentially to the upper surface , causing a 5 mm displacement relative to the lower surface. Following observations are made regarding the block.(i) the shearing stress developed on the surface is 68.1 Pa(ii) the shearing strain developed on surface is 0.25 Pa(iii) the shear modulus of material is 272.4 N/m2Regarding above statements we can say
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
Only statement (i) and (iii) are correct
b
Only statement (ii).and (iii) are correct
c
Only statements (i) and (ii) are correct
d
All the statements are correct.
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Stress=FA=0.24536×10−4=68.1Pastrain=θ=rh=520=0.25Shear modulus= S=FAtanθ=68.40.25=272.4N/m2
Watch 3-min video & get full concept clarity