A block is gently placed on a conveyor belt moving horizontally with constant speed. After t = 4s, the velocity of the block becomes equal to the velocity of the belt. If the coefficient of friction between the block and the belt is μ= 0.2, then the velocity of the conveyor belt is

Fr=μmg = 0.2 mg.                                  A = 0.2 g = 2m/s2                                  Let. velocity of belt = V0                                  So, vel. of block with respect belt will be V0                                  U =V0, A = 2,    t = 4,   v = 0                                  0 = V0– 2 × 4                                 V0= 8 m/s