First slide

Application of Newtons laws

Question

A block A has a velocity of 0.6 ms^-1 to the right. Determine the velocity of cylinder B.

Moderate

A

1.2 m s^-1
B

2.4 m s^-1
C

1.8 m s^-1
D

3.6 m s^-1

Solution

Tx(Hanged part) - 2Tx' (Sliding part)
$∴ x = 3 x^{'} \Rightarrow x = 3 \times 0.6 = 1.8 {ms}^{- 1}$

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