A block having mass m collides with an another stationary block having mass $$2$$ m. The lighter block comes to rest after collision. If the velocity of first block is v, then the value of coefficient of restitution will must be [AIIMS $$2015$$]

Question

Infinity Learn · Accepted Answer

Let the velocity of block of mass $$2$$ m after the collision be v', then from law of conservation of momentum,                     $$mv=2mv$$'⇒v'$$=v2Now$$, the coefficient of restitution,                      $$e=velocity$$ of separationvelocity of $$approach=$$ v'$$v=v/2v=12=0.5$$

A block having mass m collides with an another stationary block having mass 2 m. The lighter block comes to rest after collision. If the velocity of first block is v, then the value of coefficient of restitution will must be [AIIMS 2015]

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