First slide

Change of state

Question

A block of ice of mass 50 kg is pushed out on a horizontal plane with a velocity of 5 m/s. Due to friction, it comes to rest after covering a distance of 25 m. How much ice melts?

Moderate

A

1.86 g
B

1.43 g
C

1.33 g
D

1.75 g

Solution

We have
$m = \frac{W}{JL} = \frac{{mv}^{2}}{2 JL} = \frac{50 \times 25}{2 \times 4 .2 \times 80} = 1 .86 g$
where L is the latent heat of ice (80 cal/g).

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