Q.

A block of ice of mass 50 kg is sliding on a horizontal plane. It starts with speed 5 ms-1 and stops after moving through some distance. The mass of ice that has melted due to friction between the block and the surface is (Assuming that no energy is lost and latent heat of fusion of ice is 80 cal g -1 , J = 4.2 J cal-1)

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a

2.86 g

b

3.86 g

c

0.86 g

d

1.86 g

answer is D.

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Detailed Solution

Given,   m=50kg,v=5ms−1,L=80calg−1J=42Jcal−1 and m=?Heat lost, i.e. Q1 = work done = K (kinetic energy)=12mv2=12×50×52=625Jand heat gained, i.e.   Q2=m'×L=80×m'×4.2∵   Q1  =  Q2625=m'×8×42⇒m'=1.86g
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