Q.

A block of ice of mass M=13.44 kg slides on a horizontal surface. It starts with a speed v=10.0 m/s and finally stops after moving a distance s = 30 m. What is the mass ofice (in grams) that has melted due to friction between block and surface? Latent heat of fusion of ice is Lf=80 cal/g.

Moderate

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By Expert Faculty of Sri Chaitanya

answer is 0002.00.

(Detailed Solution Below)

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Detailed Solution

Work done by friction,W=12Mv2=12×13.44×(10)2=672J=6724.2calIf m mass of ice will melt, we have 6724.2=m(80)The mass of ice that has melted m=67280×4.2=2.0g

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