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Questions  

A block is kept on an inclined plane of inclination θ of length l. The velocity of particle at the bottom of inclined plane is (the coefficient of friction is μ)

a
2gl ⁡(μcos ⁡θ−sin ⁡θ)
b
2gl⁡ (sin⁡ θ−μcos⁡ θ)
c
2gl(sin⁡ θ+μcos⁡ θ)
d
2gl(cos ⁡θ+μsin ⁡θ)

detailed solution

Correct option is B

Acceleration  (a) =g(sin⁡θ−μcos⁡θ) and s=lu=2as=2gl(sin ⁡θ−μcos⁡ θ).

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