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Q.

A block is kept on an inclined plane of inclination θ of length l. The velocity of particle at the bottom of inclined plane is (the coefficient of friction is μ)

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a

2gl ⁡(μcos ⁡θ−sin ⁡θ)

b

2gl⁡ (sin⁡ θ−μcos⁡ θ)

c

2gl(sin⁡ θ+μcos⁡ θ)

d

2gl(cos ⁡θ+μsin ⁡θ)

answer is B.

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Detailed Solution

Acceleration  (a) =g(sin⁡θ−μcos⁡θ) and s=lu=2as=2gl(sin ⁡θ−μcos⁡ θ).
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