A block is kept on an inclined plane of inclination θ of length l. The velocity of particle at the bottom of inclined plane is (the coefficient of friction is μ)
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a
2gl (μcos θ−sin θ)
b
2gl (sin θ−μcos θ)
c
2gl(sin θ+μcos θ)
d
2gl(cos θ+μsin θ)
answer is B.
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Detailed Solution
Acceleration (a) =g(sinθ−μcosθ) and s=lu=2as=2gl(sin θ−μcos θ).